# 1. Arrange fluids for case (a) and materials for case (b) below having from the highest to lowest…

1. Arrange fluids for case (a) and materials for case (b)
below having from the highest to lowest magnitude of the fin efficiency for
identical corrugated plain fin geometry in a given heat exchanger.

(a) air, water, viscous oil (b) stainless steel, copper,
aluminum

2. A counterflow ceramic vehicular gas turbine recuperator
operates at the following conditions: Air and gas inlet temperatures are 234
and 7308C, respectively, air and gas flow rates are 0.57 and 0.59 kg/s,
respectively, and the product of the overall heat transfer coefficient and heat
transfer area is 6650 W/K. The cross-
View complete question »

1. Arrange fluids for case (a) and materials for case (b)
below having from the highest to lowest magnitude of the fin efficiency for
identical corrugated plain fin geometry in a given heat exchanger.

(a) air, water, viscous oil (b) stainless steel, copper,
aluminum

2. A counterflow ceramic vehicular gas turbine recuperator
operates at the following conditions: Air and gas inlet temperatures are 234
and 7308C, respectively, air and gas flow rates are 0.57 and 0.59 kg/s,
respectively, and the product of the overall heat transfer coefficient and heat
transfer area is 6650 W/K. The cross-sectional area for longitudinal conduction
is 0.03226 m2 and the core length is 101.6 mm. Calculate the air and gas outlet
temperatures with and without longitudinal wall heat conduction. Consider air
and gas specific heats as 1.08 and 1.09 kJ/kg K, respectively and the thermal
conductivity of the ceramic material kw as 3.12 W/m K. Discuss the
results.

View less »